Bvron Purchased A Box Of Candy At The Store. On His Way Home He Ate 1/4 Of The Candy In The Box. At Dinner With Friends Later That Night He Served 1/2

Bvron purchased a box of candy at the store. On his way home he ate 1/4 of the candy in the box. At dinner with friends later that night he served 1/2 of what was left. If there are 6 chocolates now left in the box, how many did the box contain to start with?

Answer:

The box originally contain 16 candies.

Explanation and computation:

Let 8x represent the original number of candies in the box.

As Byron ate ¹/₄ then served ¹/₂ of whats left at dinner and remaining 6 chocolates, the following equation is formulated.

8x-8x(\frac{1}{4})-\frac{1}{2}8x-8x(\frac{1}{4})=6

Solution

8x-8x(\frac{1}{4})-\frac{1}{2}8x-8x(\frac{1}{4})=6\\\\\:8x-2x-\frac{1}{2}8x-2x=6\\\\\:6x-\frac{1}{2}6x=6\\\\\:6x-3x=6\\\\3x=6\\\\x=6/3=2\\\\(substituting\:2\:for\:x\:\:in\:8x)\\\\8x=8(2)=\boxed{16}


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